What are the intercepts of : $8y= - 2x - 9$ ?

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Answer 1 · 2016-04-09T10:18:18

$x$ intercept: $(-9/2, 0)$
$y$ intercept: $(0, -9/8)$

$x$ intercepts where $y=0$
Therefore, substitute $y=0$ and solve for $x$ .

$0=-2x-9$
$9=-2x$
$-9/2=x$

Therefore, $x$ intercept at $(-9/2, 0)$

$y$ intercepts where $x=0$
Therefore, substitute $x=0$ and solve for $y$ .

$8y=-9$
$y=-9/8$

Therefore, $y$ intercept at $(0, -9/8)$

Tony B

What are the intercepts of : 8y= - 2x - 98y= - 2x - 9?