What are the intercepts of $- 8 y - 6 x = 1$ $-8y-6x=1$ ?

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Answer 1 · 2016-01-19T02:36:32

x-intercept is $= - \frac{1}{6}$ $=-1/6$

y-intercept is $= - \frac{1}{8}$ $=-1/8$

$- 8 y - 6 x = 1$ $-8y-6x=1$
$- 6 x - 8 y = 1$ $-6x-8y=1$

The given equation is in the form
$a x + b y = c$ $ax+by=c$

In such case its -

x-intercept is $= \frac{c}{a} = \frac{1}{- 6} = - \frac{1}{6}$ $=c/a=1/(-6)=-1/6$

y-intercept is $= \frac{c}{b} = \frac{1}{- 8} = - \frac{1}{8}$ $=c/b=1/(-8)=-1/8$

What are the intercepts of −8y−6x=1-8y-6x=1?