What are the intercepts of -x+3y=-3x+3y=3?

1 Answer
Mar 6, 2018

The x-intercept is (3,0)(3,0).

The y-intercept is (0,-1)(0,1).

Explanation:

Given:

-x+3y=-3x+3y=3 is a linear equation in standard form:

Ax+By=CAx+By=C.

X-intercept: value of xx when y=0y=0.

Substitute 00 for yy and solve for xx.

-x+3(0)=-3x+3(0)=3

-x=-3x=3

Multiply both sides by -11.

x=3x=3

The x-intercept is (3,0)(3,0).

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Y-intercept: value of yy when x=0x=0

Substitute 00 for xx and solve for yy.

0+3y=-30+3y=3

3y=-33y=3

Divide both sides by 33.

(color(red)cancel(color(black)(3))^1y)/(color(red)cancel(color(black)(3))^1)=-color(red)cancel(color(black)(3))^1/color(red)cancel(color(black)(3))^1

y=-1

The y-intercept is (0,-1).

You can graph this equation by plotting the x- and y-intercepts and drawing a straight line through them.

graph{-x+3y=-3 [-11.25, 11.25, -5.625, 5.625]}