What are the intercepts of $-x-4y=11$ ?

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Answer 1 · 2018-03-25T04:05:09

The x-intercept is $(-11,0)$ .

The y-intercept is $(0,-11/4)$ or $(0,-2.75)$ .

Given:

$-x-4y=11$

Multiply by $-1$ . This will reverse the signs.

$x+4y=-11$

The x-intercept is the value of $x$ when $y=0$ .

Substitute $0$ for $y$ .

$x+4(0)=-11$

$x=-11$

The x-intercept is $(-11,0)$ .

The y-intercept is the value of $y$ when $x=0$ .

Substitute $0$ for $x$ .

$0+4y=-11$

$4y=-11$

Divide both sides by $4$ .

$y=-11/4=-2.75$

The y-intercept is $(0,-11/4)$ or $(0,-2.75)$ .

graph{(-x-4y-11)(x+4y+11)=0 [-10, 10, -5, 5]}

What are the intercepts of -x-4y=11-x-4y=11?