What are the points of inflection, if any, of $f(x)=2x^3 + 8x^2$ ?

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Answer 1 · 2017-01-28T05:07:32

At $x=-4/3$ there is point of inflection

Given -

$y=2x^3+8x^2$

To find the point of inflection put send derivative equal to zero and find the value of $x$

$dy/dx=6x^2+16x$

$(d^2y)/(dx^2)=12x+16$

$(d^2y)/(dx^2)=0 => 12x+16=0$

$x=(-16)/12=-4/3$

graph{2x^3+8x^2 [-10, 10, -5, 5]}

What are the points of inflection, if any, of f(x)=2x^3 + 8x^2 f(x)=2x^3 + 8x^2 ?