What are the points of inflection, if any, of f(x)=2x3+8x2?
1 Answer
Jan 28, 2017
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Explanation:
Given -
y=2x3+8x2
To find the point of inflection put send derivative equal to zero and find the value of
dydx=6x2+16x
d2ydx2=12x+16
d2ydx2=0⇒12x+16=0
x=−1612=−43
graph{2x^3+8x^2 [-10, 10, -5, 5]}