What are the points of inflection, if any, of #f(x)=2x^3 + 8x^2 #?
1 Answer
Jan 28, 2017
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Explanation:
Given -
#y=2x^3+8x^2#
To find the point of inflection put send derivative equal to zero and find the value of
#dy/dx=6x^2+16x#
#(d^2y)/(dx^2)=12x+16#
#(d^2y)/(dx^2)=0 => 12x+16=0#
#x=(-16)/12=-4/3#
graph{2x^3+8x^2 [-10, 10, -5, 5]}
