What are the points of inflection, if any, of #f(x)=-3x^3+270x^2-3600x+18000 #?
1 Answer
Oct 28, 2016
At
Explanation:
Given -
#y=-3x^3+270x^2-3600x+18000#
To find the point of inflection we have to set the send derivative equal to zero.
#dy/dx=9x^2+540x-3600#
#(d^2y)/(dx^2)=18x+540#
Set
Then -
#18x+540=0#
#x=540/18=30#
At