What are the points of inflection, if any, of #f(x)=sqrt(xe^(-x^2) #?
1 Answer
Nov 19, 2016
Explanation:
#4x^4-8x^2-1=0 to x = 1+sqrt5/2=2.118, nearly
f'''=f'(x^2-2-1/(4x^2))+f(2x+1/(2x^3))=0+ positive number, at the zero
x=2.118 of f''.
Conclusion: x = 2.118, nearly, is a point of inflexion. I am fortunate.
The graph supports me, showing tangent crossing the curve, here.
graph{sqrt (x e^(-x^2) [-5, 5, -2.5, 2.5]}