What are the points of inflection, if any, of #f(x)=xsin^2x # on [0,2pi]?
1 Answer
points corresponding to
between
correct to one decimal place
and
Explanation:
Given:
Evaluating the curvature,
=
=
Since,
Thus,
=
Now,
implies
Taking
Either
where, x is clearly
or
By trial and error,
Inspecting for values between 0 and 2pi in the intervals of 0.1pi
At
between
correct to one decimal place
MY thanks for Fleur for reminding