What are the points of inflection of #f(x)=4 / (2x^2#?
1 Answer
Sep 8, 2016
No points of inflection.
Explanation:
We have:
First, let's evaluate the second derivative of this function using the "quotient rule":
Then, to determine the points of inflection, we need to set the second derivative equal to zero, and then solve for
Therefore, there are no points of inflection for