What does $\frac{x^{2} + 4 x + 4}{x + 2}$ $(x^2+4x+4) / (x+2)$ equal?

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What does $\frac{x^{2} + 4 x + 4}{x + 2}$ $(x^2+4x+4) / (x+2)$ equal?

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Answer 1 · 2015-10-23T04:29:17

(x+2)

Explanation:

Here,

$x^{2}$ $x^2$ + 4x +4
= ${(x)}^{2}$ $(x)^2$ + 22x + ${(2)}^{2}$ $(2)^2$
= ${(x + 2)}^{2}$ $(x+2)^2$
=(x+2)(x+2)

We replace this value in the question.
So
$\frac{(x + 2) (x + 2)}{(x + 2)}$ ${(x+2)(x+2)}/((x+2)$
We cancel one (x+2) in the numerator with the one in the denominator.

SO we have (x+2)

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What does $\frac{x^{2} + 4 x + 4}{x + 2}$ $(x^2+4x+4) / (x+2)$ equal?

1 Answer

Explanation:

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What does $\frac{x^{2} + 4 x + 4}{x + 2}$ $(x^2+4x+4) / (x+2)$ equal?