What is $f (x) = \int \sqrt{x + 8} d x$ $f(x) = int sqrt(x+8) dx$ if $f (2) = - 3$ $f(2)=-3$ ?

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Answer 1 · 2017-04-14T21:30:53

I got: $f (x) = \frac{2}{3} \sqrt{{(x + 8)}^{3}} - \frac{9 + 20 \sqrt{10}}{3}$ $f(x)=2/3sqrt((x+8)^3)-(9+20sqrt(10))/3$

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What is f(x) = int sqrt(x+8) dxf(x)=∫√x+8dxf(x) = int sqrt(x+8) dx if f(2)=-3 f(2)=−3f(2)=-3 ?