Question

What is `f(x) = int x^2-3 dx` if `f(3)=-2`?

Answer 1

`f(x)=x^3/3-3x-2`

Explanation:

`int(x^2-3dx)=x^3/3-3x+C`.

Now substituting the initial boundary condition in we get

`f(3)=-2`

`therefore3^3/3-3(3)+C=-2`

`therefore C=-2`.

`therefore` the required function is `f(x)=x^3/3-3x-2`.