What is #f(x) = int x^3-2x dx# if #f(-2)=-1 #? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer Trevor Ryan. Apr 9, 2016 #f(x)=int(x^3-2x)dx# #=x^4/4-(2x^2)/2+C# Now applying the initial boundary condition we get #f(-2)=-1=>C=-1# #therefore f(x)=1/4x^4-x^2-1# Answer link Related questions How do you find the constant of integration for #intf'(x)dx# if #f(2)=1#? What is a line integral? What is #f(x) = int x^3-x# if #f(2)=4 #? What is #f(x) = int x^2+x-3# if #f(2)=3 #? What is #f(x) = int xe^x# if #f(2)=3 #? What is #f(x) = int x - 3 # if #f(2)=3 #? What is #f(x) = int x^2 - 3x # if #f(2)=1 #? What is #f(x) = int 1/x # if #f(2)=1 #? What is #f(x) = int 1/(x+3) # if #f(2)=1 #? What is #f(x) = int 1/(x^2+3) # if #f(2)=1 #? See all questions in Evaluating the Constant of Integration Impact of this question 1441 views around the world You can reuse this answer Creative Commons License