What is #f(x) = int x^3-2x+e^x dx# if #f(2) = 5 #? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer Leland Adriano Alejandro Jan 16, 2016 #f(x)=x^4/4-x^2+e^x-e^2+5# Explanation: #f(x)=int (x^3-2x+e^x) dx+C# #f(x)=x^4/4-x^2+e^x+C# #f(2)=5=2^4/4-2^2+e^2+C# first equation #5=4-4+e^2+C# #C=5-e^2# therefore from the first equation #f(x)=x^4/4-x^2+e^x-e^2+5# Answer link Related questions How do you find the constant of integration for #intf'(x)dx# if #f(2)=1#? What is a line integral? What is #f(x) = int x^3-x# if #f(2)=4 #? What is #f(x) = int x^2+x-3# if #f(2)=3 #? What is #f(x) = int xe^x# if #f(2)=3 #? What is #f(x) = int x - 3 # if #f(2)=3 #? What is #f(x) = int x^2 - 3x # if #f(2)=1 #? What is #f(x) = int 1/x # if #f(2)=1 #? What is #f(x) = int 1/(x+3) # if #f(2)=1 #? What is #f(x) = int 1/(x^2+3) # if #f(2)=1 #? See all questions in Evaluating the Constant of Integration Impact of this question 1082 views around the world You can reuse this answer Creative Commons License