What is #f(x) = int x-3e^(x)dx# if #f(0)=-2 #? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer Cem Sentin Dec 20, 2017 #f(x)=x^2/2-3e^x+1# Explanation: #f(x)=int (x-3e^x)*dx=x^2/2-3e^x+C# After imposing #f(0)=-2# condition, I found #C-3=-2#, so #C=1# Thus, #f(x)=x^2/2-3e^x+1# Answer link Related questions How do you find the constant of integration for #intf'(x)dx# if #f(2)=1#? What is a line integral? What is #f(x) = int x^3-x# if #f(2)=4 #? What is #f(x) = int x^2+x-3# if #f(2)=3 #? What is #f(x) = int xe^x# if #f(2)=3 #? What is #f(x) = int x - 3 # if #f(2)=3 #? What is #f(x) = int x^2 - 3x # if #f(2)=1 #? What is #f(x) = int 1/x # if #f(2)=1 #? What is #f(x) = int 1/(x+3) # if #f(2)=1 #? What is #f(x) = int 1/(x^2+3) # if #f(2)=1 #? See all questions in Evaluating the Constant of Integration Impact of this question 1246 views around the world You can reuse this answer Creative Commons License