What is $f (x) = \int x e^{x} - x^{2} d x$ $f(x) = int xe^x-x^2 dx$ if $f (- 1) = 1$ $f(-1) = 1$ ?

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Answer 1 · 2016-08-22T20:39:40

I found: $f (x) = x e^{x} - e^{x} - \frac{x^{3}}{3} + 2 (\frac{1}{3} + \frac{1}{e})$ $f(x)=xe^x-e^x-x^3/3+2(1/3+1/e)$

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What is f(x) = int xe^x-x^2 dxf(x)=∫xex−x2dxf(x) = int xe^x-x^2 dx if f(-1) = 1 f(−1)=1f(-1) = 1 ?