What is #f(x) = int xsin4x+tanx dx# if #f(pi/4)=1 #? Calculus Techniques of Integration Evaluating the Constant of Integration 1 Answer A. S. Adikesavan Feb 15, 2017 #1/16(-4xcos(4x)+sin(4x)-16ln cosx-pi+15-8ln 2)# Explanation: #f(x)=int(-1/4xd(cos(4x))-1/((sinx)') d(cosx))# #=-1/4(x cos(4x)-intcos(4x dx))-lncosx# #=-1/4xcos(4x)+1/16sin(4x)-logcosx +C# As #f(pi/4)=1#, #pi/16+1/16-ln(1/sqrt2)+C=1# So, #C =-pi/16+15/16-1/2ln2#. And so, #f(x)=-1/4xcos(4x)+1/16sin(4x)-logcosx -pi/16+15/16-1/2ln2# #=1/16(-4xcos(4x)+sin(4x)-16ln cosx-pi+15-8ln 2)# Answer link Related questions How do you find the constant of integration for #intf'(x)dx# if #f(2)=1#? What is a line integral? What is #f(x) = int x^3-x# if #f(2)=4 #? What is #f(x) = int x^2+x-3# if #f(2)=3 #? What is #f(x) = int xe^x# if #f(2)=3 #? What is #f(x) = int x - 3 # if #f(2)=3 #? What is #f(x) = int x^2 - 3x # if #f(2)=1 #? What is #f(x) = int 1/x # if #f(2)=1 #? What is #f(x) = int 1/(x+3) # if #f(2)=1 #? What is #f(x) = int 1/(x^2+3) # if #f(2)=1 #? See all questions in Evaluating the Constant of Integration Impact of this question 1410 views around the world You can reuse this answer Creative Commons License