What is the angular momentum of a rod with a mass of $2 k g$ $2 kg$ and length of $5 m$ $5 m$ that is spinning around its center at $3 H z$ $3 Hz$ ?

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Answer 1 · 2017-04-02T09:57:55

The angular momentum is $= 78.5 k g m^{2} s^{- 1}$ $=78.5kgm^2s^-1$

The angular momentum is $L = I ω$ $L=Iomega$

where $I$ $I$ is the moment of inertia

and $ω$ $omega$ is the angular velocity

The moment of inertia of a rod, rotating about the center is

$I = \frac{1}{12} \cdot m L^{2}$ $I=1/12*mL^2$

$= \frac{1}{12} \cdot 2 \cdot 5^{2} = \frac{25}{6} k g m^{2}$ $=1/12*2*5^2= 25/6 kgm^2$

The angular velocity is $ω = 3 \cdot 2 π r a d s^{- 1}$ $omega=3*2pi rads^-1$

The angular momentum is

$L = \frac{25}{6} \cdot 6 π k g m^{2} s^{- 1}$ $L=25/6*6pikgm^2s^-1$

$= 25 π k g m^{2} s^{- 1}$ $=25pikgm^2s^-1$

$= 78.5 k g m^{2} s^{- 1}$ $=78.5kgm^2s^-1$

What is the angular momentum of a rod with a mass of 2kg2 kg and length of 5m5 m that is spinning around its center at 3Hz3 Hz?