What is the angular momentum of a rod with a mass of $2 k g$ $2 kg$ and length of $6 m$ $6 m$ that is spinning around its center at $3 H z$ $3 Hz$ ?

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What is the angular momentum of a rod with a mass of $2 k g$ $2 kg$ and length of $6 m$ $6 m$ that is spinning around its center at $3 H z$ $3 Hz$ ?

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Answer 1 · 2016-02-13T11:20:09

$P = 36 π$ $P=36 pi$

Explanation:

$P: angular momentum$ $"P: angular momentum"$
$ω : angular velocity$ $omega:"angular velocity"$
$I:moment of inertia$ $"I:moment of inertia"$
$I = m \cdot \frac{l^{2}}{12} for rod spinning around its center$ $I=m*l^2/12" for rod spinning around its center"$
$P = I \cdot ω$ $P=I*omega$
$P = \frac{m \cdot l^{2}}{12} \cdot 2 \cdot π \cdot f$ $P=(m*l^2)/12 *2*pi*f$
$P=(cancel(2)*6^2)/cancel(12) *cancel(2)*pi*cancel(3)$
$P=36 pi$

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What is the angular momentum of a rod with a mass of $2 k g$ $2 kg$ and length of $6 m$ $6 m$ that is spinning around its center at $3 H z$ $3 Hz$ ?

1 Answer

Explanation:

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What is the angular momentum of a rod with a mass of $2 k g$ $2 kg$ and length of $6 m$ $6 m$ that is spinning around its center at $3 H z$ $3 Hz$ ?