What is the angular momentum of a rod with a mass of $2 kg$ and length of $7 m$ that is spinning around its center at $3 Hz$ ?

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Answer 1 · 2017-03-22T16:16:39

The angular momentum is $=153.9kgm^2s^-1$

The angular momentum is $L=Iomega$

and $omega$ is the angular velocity

The moment of inertia of a rod, rotating about the center is

$I=1/12*mL^2$

$=1/12*2*7^2= 49/6 kgm^2$

The angular velocity is

$omega=3*2pi=(6pi) rads^-1$

The angular momentum is

$L=49/6*(6pi)=153.9kgm^2s^-1$

What is the angular momentum of a rod with a mass of 2 kg2 kg and length of 7 m7 m that is spinning around its center at 3 Hz3 Hz?