What is the angular momentum of a rod with a mass of $2 kg$ and length of $9 m$ that is spinning around its center at $52 Hz$ ?

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Answer 1 · 2017-03-08T07:38:00

The angular momentum is $=4410.8kgm^2s^-1$

The angular momentum is $L=Iomega$

The moment of inertia of a rod, rotating about the center is

$I=1/12*mL^2$

$=1/12*2*9^2= 27/2 kgm^2$

The angular velocity is

$omega=52*2pi=104pirads^-1$

The angular momentum is

$L=I omega=27/2*104pi=4410.8kgm^2s^-1$

What is the angular momentum of a rod with a mass of 2 kg2 kg and length of 9 m9 m that is spinning around its center at 52 Hz52 Hz?