What is the angular momentum of a rod with a mass of $6 kg$ and length of $4 m$ that is spinning around its center at $3 Hz$ ?

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Answer 1 · 2017-12-16T09:34:23

The angular momentum is $=150.8kgm^2$

The angular momentum is $L=Iomega$

and $omega$ is the angular velocity

The moment of inertia of a rod, rotating about the center is

$I=1/12*mL^2$

The mass of the rod is $m=6kg$

The length of the rod is $L=4m$

Therefore, the moment of inertia is

$L=1/12*6*4^2= 8 kgm^2$

The frequency is $f=3Hz$

The angular velocity is $omega=2*pi*f=6pi$

Then,

The angular momentum is

$L=Iomega=8*6pi=48pi=150.8kgm^2$

What is the angular momentum of a rod with a mass of 6 kg 6 kg and length of 4 m4 m that is spinning around its center at 3 Hz3 Hz?