What is the angular momentum of a rod with a mass of 8 kg8kg and length of 4 m4m that is spinning around its center at 5 Hz5Hz?
1 Answer
Mar 9, 2016
Explanation:
The moment of inertia of a homogenous rod with mass
I = 1/12 ML^2
= 1/12 (8 quad "kg") (4 quad "m")^2
= 10.67 quad "kgm"^2
The angular momentum about the center of the rod is given by
L = I omega
= (10.67 quad "kgm"^2)(5 quad "Hz")
53.3 quad "kgm"^2"s"^{-2}