What is the angular momentum of a rod with a mass of 8 kg8kg and length of 4 m4m that is spinning around its center at 5 Hz5Hz?

1 Answer
Mar 9, 2016

L = 53.3 quad "kgm"^2"s"^{-2}

Explanation:

The moment of inertia of a homogenous rod with mass M and length L about its center, I, is given by

I = 1/12 ML^2

= 1/12 (8 quad "kg") (4 quad "m")^2

= 10.67 quad "kgm"^2

The angular momentum about the center of the rod is given by

L = I omega

= (10.67 quad "kgm"^2)(5 quad "Hz")

53.3 quad "kgm"^2"s"^{-2}