Question

What is the angular momentum of a rod with a mass of `8 kg` and length of `7 m` that is spinning around its center at `5 Hz`?

Answer 1

`P_a=326,666666667 pi`

Explanation:

`P_a :"angular momentum"`
`P_a=I* omega`
`omega =2*pi * f`
`omega=2*pi*5=10*pi`
`I=m*L^2/12 "for rod spinning its center"`
`I=8*7^2/12=32,6666666667`
`P_a=10 pi .32,6666666667`
`P_a=326,666666667 pi`