What is the angular momentum of an object with a mass of $3 k g$ $3 kg$ that moves along a circular path of radius $12 m$ $12 m$ at a frequency of $\frac{2}{3} H z$ $2/3 Hz$ ?

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Answer 1 · 2017-06-20T18:14:20

The angular momentum is $= 1809.6 k g m^{2} s^{- 1}$ $=1809.6kgm^2s^-1$

The angular momentum is $L = I ω$ $L=Iomega$

where $I$ $I$ is the moment of inertia

and $ω$ $omega$ is the angular velocity

The moment of inertia of the object is

$I = m r^{2} = 3 \cdot 12^{2} = 432 k g m^{2}$ $I=mr^2=3*12^2=432kgm^2$

The angular velocity is

$ω = 2 \cdot π \cdot f = 2 π \cdot \frac{2}{3} = \frac{4}{3} π r a d s^{- 1}$ $omega=2*pi*f=2pi*2/3=4/3pi rads^-1$

The angular momentum is

$L = I ω = 432 \cdot \frac{4}{3} π = 1809.6 k g m^{2} s^{- 1}$ $L=I omega=432*4/3pi=1809.6kgm^2s^-1$