What is the angular momentum of an object with a mass of $4 k g$ $4 kg$ that moves along a circular path of radius $2 m$ $2 m$ at a frequency of $1 H z$ $1 Hz$ ?

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What is the angular momentum of an object with a mass of $4 k g$ $4 kg$ that moves along a circular path of radius $2 m$ $2 m$ at a frequency of $1 H z$ $1 Hz$ ?

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Answer 1 · 2018-03-04T06:57:33

Angular momentum is expressed as $I ω$ $Iomega$ (where, $I$ $I$ is the moment of inertia and $ω$ $omega$ is the angular velocity)

In this case given, $ν = 1 H z$ $nu=1 Hz$

we know, $ω = 2 π ν = 2 π \cdot 1 = 2 π r a d s^{- 1}$ $omega =2pinu=2pi*1=2pi rads^-1$

And moment of inertia of the object,w.r.t the centre of thr circular pathway it is moving is $M r^{2} = 4 \cdot {(2)}^{2} = 16 K g . m^{2}$ $Mr^2 =4*(2)^2 =16Kg.m^2$

So,angular momentum of this object is $16 \cdot 2 π = 100.531 K g m^{2} r a d s^{- 1}$ $16*2pi=100.531Kgm^2rads^-1$

Answer 2 · 2018-03-04T07:57:18

The angular momentum is $= 100.5 k g m^{2} s^{- 1}$ $=100.5kgm^2s^-1$

Explanation:

The angular momentum is $L = I ω$ $L=Iomega$

where $I$ $I$ is the moment of inertia

The mass of the object is $m = 4 k g$ $m=4kg$

The radius of the path is $r = 2 m$ $r=2m$

The moment of inertia of the object is given by

$I = m r^{2}$ $I=mr^2$

$= 4 \cdot 2^{2} = 16 k g m^{2}$ $=4*2^2= 16 kgm^2$

The frequency is $f = 1 H z$ $f=1Hz$

The angular velocity is $ω = 2 π f = 2 \cdot 1 \cdot π = 2 π r a d s^{- 1}$ $omega=2pif=2*1*pi=2pirads^-1$

The angular momentum is

$L = I ω = 16 \cdot 2 π = 100.5 k g m^{2} s^{- 1}$ $L=Iomega=16*2pi=100.5kgm^2s^-1$

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What is the angular momentum of an object with a mass of $4 k g$ $4 kg$ that moves along a circular path of radius $2 m$ $2 m$ at a frequency of $1 H z$ $1 Hz$ ?

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Explanation:

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What is the angular momentum of an object with a mass of $4 k g$ $4 kg$ that moves along a circular path of radius $2 m$ $2 m$ at a frequency of $1 H z$ $1 Hz$ ?