What is the angular momentum of an object with a mass of $5 k g$ $5 kg$ that moves along a circular path of radius $3 m$ $3 m$ at a frequency of $18 H z$ $18 Hz$ ?

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Answer 1 · 2018-03-14T12:33:53

$5089.38\ "kg m"^2//"s"$

Angular momentum ( $L$ ) is given as

$L = I ω$

$L = mr^2 × 2 π f$

Moment of inertia of small object is $mr^2$ ; $omega = 2 π f$

$L = "5 kg" × ("3 m")^2 × 2 × π × "18 Hz" = 5089.38\ "kg m"^2//"s"$

Answer 2 · 2018-03-14T14:29:16

The angular momentum is $=5089.4kgm^2s^-1$

The angular momentum is $L=Iomega$

The mass of the object is $m=5kg$

The radius of the path is $r=3m$

The moment of inertia of the object is given by

$I=mr^2$

$=5*3^2= 45 kgm^2$

The frequency is $f=18Hz$

The angular velocity is $omega=2pif=2*18*pi=36pirads^-1$

The angular momentum is

$L=Iomega=45*36pi=5089.4kgm^2s^-1$

What is the angular momentum of an object with a mass of 5 kg5kg5 kg that moves along a circular path of radius 3 m3m3 m at a frequency of 18 Hz 18Hz 18 Hz ?