What is the angular momentum of an object with a mass of $7 k g$ $7 kg$ that moves along a circular path of radius $12 m$ $12 m$ at a frequency of $\frac{2}{3} H z$ $2/3 Hz$ ?

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What is the angular momentum of an object with a mass of $7 k g$ $7 kg$ that moves along a circular path of radius $12 m$ $12 m$ at a frequency of $\frac{2}{3} H z$ $2/3 Hz$ ?

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Answer 1 · 2016-01-29T18:10:11

$L = 1344 π N s^{- 1}$ $L=1344\piNs^-1$

Explanation:

Angular momentum of an object is $L = m v r$ $L=mvr$

Given that $m = 7 k g$ $m=7kg$ , $r = 12 m$ $r=12m$ and $ω = 4 \frac{π^{c}}{3}$ $\omega=4\pi^c/3$ (They had given us linear frequency, not angular frequency)

They haven't given us $v$ $v$ directly. But, we know that $v = ω r$ $v=\omegar$ , so let's get that into the angular momentum equation, which means
$L = m ω r^{2}$ $L=m\omegar^2$

I'm sure you'll now understand how I got that $π$ $\pi$ there in the answer now.

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What is the angular momentum of an object with a mass of $7 k g$ $7 kg$ that moves along a circular path of radius $12 m$ $12 m$ at a frequency of $\frac{2}{3} H z$ $2/3 Hz$ ?

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Explanation:

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What is the angular momentum of an object with a mass of $7 k g$ $7 kg$ that moves along a circular path of radius $12 m$ $12 m$ at a frequency of $\frac{2}{3} H z$ $2/3 Hz$ ?