Question

What is the antiderivative of `1/x^3`?

Answer 1

`-1/(2x^2)+C`

Explanation:

`intx^ndx=x^(n+1)/(n+1)+C`, where `n!=-1`.

So `int1/x^3dx=intx^(-3)dx=-1/2x^(-2)+C=-1/(2x^2)+C`