What is the antiderivative of #4/x^2#?

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What is the antiderivative of #4/x^2#?

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Answer 1 · 2016-02-16T16:41:27

I found: #-4/x+c#

Explanation:

We can manipulate and integrate it to get:
antiderivative#=int4/x^2dx=int4x^-2dx=4intx^-2dx=#
#=4x^(-2+1)/(-2+1)+c=-4x^-1+c=-4/x+c#

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What is the antiderivative of #4/x^2#?

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