What is the antiderivative of #ln(x)/x#? Calculus Introduction to Integration Integrals of Exponential Functions 1 Answer Alan N. Feb 21, 2017 #ln^2(x)/2 +C# Explanation: #I=int lnx/x dx# Let #u=lnx# #(du)/dx = 1/x -> dx=x du# [Standard differential] #:. I= int u/x * x du = int u du# #= u^2/2 # [Power rule] Undo u substitution: #I = ln^2 (x)/2 +C# Answer link Related questions How do you evaluate the integral #inte^(4x) dx#? How do you evaluate the integral #inte^(-x) dx#? How do you evaluate the integral #int3^(x) dx#? How do you evaluate the integral #int3e^(x)-5e^(2x) dx#? How do you evaluate the integral #int10^(-x) dx#? What is the integral of #e^(x^3)#? What is the integral of #e^(0.5x)#? What is the integral of #e^(2x)#? What is the integral of #e^(7x)#? What is the integral of #2e^(2x)#? See all questions in Integrals of Exponential Functions Impact of this question 1337 views around the world You can reuse this answer Creative Commons License