What is the antiderivative of #(x+4)^2#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer ali ergin Aug 6, 2016 #int(x+4)^2 d x=1/3(x+4)^3+C# Explanation: #int (x+4)^2 d x=?# #"Substitute "u=x+4# #d u=d x# #int(x+4)^2 d x=int u^2*d u# #int u^2 *d u=1/3 u^3# #int (x+4)^2 d x=1/3 u^3# #"Undo substitution"# #int(x+4)^2 d x=1/3(x+4)^3+C# Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 4052 views around the world You can reuse this answer Creative Commons License