What is the approximate energy of a photon having a frequency of #4*10^7# #Hz#?

1 Answer
Jul 26, 2016

#E = 2.6xx10^(-26)J#

Explanation:

#color(coral)("To determine the answer, we will use the equation below:")#

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We know h and v, so all we have to do is plug the known values into the equation and solve for E like this:

#E = (6.6xx10^(-34)Jxxcancels)xx(4xx10^(7)cancels^(-1))#

Thus, #E = 2.6xx10^(-26)J#

  • I should also mention that the unit Hz is the same as #s^(-1)#, I wrote it that way because I wanted you to see how the units canceled out.