What is the area of a triangle with sides of 39, 67.27 and 48.33 cm?

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Answer 1 · 2015-10-17T19:55:15

$sqrt(860255.971769)$ .

You can use Heron's formula: if $a$ , $b$ and $c$ are the sides of the triangle, then the area $A$ can be found this way:

$A=sqrt(p * (p-a) * (p-b) * (p-c))$ , where $p$ is half of the perimeter: ${a+b+c}/2$ .

So, let's compute $p$ :

$(39+67.27+48.33)/2=77.3$ .

So, the formula is

$sqrt(77.3 * (77.3-39) * (77.3-48.33) * (77.3 - 67.27))$

which is $sqrt(860255.971769)$ .