What is the area of a triangle with sides of length 4, 2, and 1?

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Answer 1 · 2018-06-22T16:49:29

This is not possible to solve in real number solutions $RR$ because it is not possible to have a triangle with sides: $4,2,1$

$(isqrt(105))/4$

To solve in the imaginary realm use Heron's formula:

$Area=sqrt(s(s-a)(s-b)(s-c))$

where $s=(a+b+c)/2$ which is the $"perimeter"/2$

sides are $4,2,1$

$s=(4+2+1)/2=7/2$

$A=sqrt(7/2(7/2-4)(7/2-2)(7/2-1))=(isqrt(105))/4$