What is the average rate of change of the function #f(z) = 2-5(z^2)# on the interval [-7,2]?

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Answer 1 · 2017-07-19T13:26:51

#25#

The average rate of change of a function #f# on an interval #[a,b]# is

#(Deltay)/(Deltax) = (f(b)-f(a))/(b-a)#

(Yes, that is the same as the slope of the line through the endpoints on the graph.)

So, for this question the answer is

#(f(2)-f(-7))/(2-(-7)) = ((2-5(2^2))-2-5((-7)^2))/9#

Do the arithmetic.

You should get #25#