Question

What is the average value of a function `sin(X)` on the interval [0, pi]?

Answer 1

`2/pi`.

Explanation:

Average`=(int sin x dx) /pi`, over the interval `[0, pi]`

The denominator is the length of the interval of integration.t.

`=[-cos x]/pi`, between the limits [0, pi]#

`--[cos pi - cos 0]`

`=-[-1-1]/pi=2/pi`.