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What is the average value of a function #y=3x^5# on the interval #[-3,3]#?

1 Answer

Nov 22, 2016

It is #0#.

Explanation:

The average value is #1/(3-(-3)) int_-3^3 3x^5 dx#

But since #int_-3^3 3x^5 dx = 0#, the average value is also #0#.

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