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What is the average value of a function $y = x^{2} - 2 x + 4$ $y=x^2-2x+4$ on the interval $[0, 8]$ $[0,8]$ ?

1 Answer

Jun 28, 2016

$= \frac{52}{3}$ $= 52/3$

Explanation:

By definition

$y_{ave} = (int_a^b \ y \ dx)/(b - a)$

so here

$y_{ave} = (int_0^8 \ x^2 - 2x + 4 \ dx)/(8-0)$

$= 1/8 [ (x^3)/3 - x^2 + 4x]_0^8$

$= 52/3$

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