Question

What is the center and radius of the circle with equation `(x-2)^2 + (y-5)^2=100`?

Answer 1

centre = (2 , 5 ) and r = 10

Explanation:

The standard form of the equation of a circle is :

`( x - a )^2 + ( y - b )^2 = r^2`

where (a , b ) is the centre and r , the radius.

compare with : `(x - 2 )^2 + (y - 5 )^2 = 100`

to obtain a = 2 , b = 5 and `r = sqrt100 = 10`