What is the concentration of a solution which contains 1 mole of $C a C l_{2}$ $CaCl_2$ dissolved in 2,000 milliliters of solution?

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Answer 1 · 2017-01-06T16:39:36

$Concentration$ $"Concentration"$ $=$ $=$ $0.5 \cdot m o l \cdot L^{- 1}$ $0.5*mol*L^-1$ with respect to ${CaCl}_{2}$ $"CaCl"_2$ .

$Concentration$ $"Concentration"$ $=$ $=$ $\frac{Moles of solute}{Volume of solution}$ $"Moles of solute"/"Volume of solution"$

$= \frac{1 \cdot m o l}{2.000 \cdot L}$ $=(1*mol)/(2.000*L)$ $=$ $=$ $0.5 \cdot m o l \cdot L^{- 1}$ $0.5*mol*L^-1$ .

In $1 L$ $"1 L"$ of solution, what is the mass of solute?

What is the concentration of a solution which contains 1 mole of CaCl2CaCl_2 dissolved in 2,000 milliliters of solution?