What is the degree of $- 5 x^{2} (x - 7) {(x + 1)}^{3} = 0$ $-5x^2(x-7)(x+1)^3=0$ ?

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Answer 1 · 2015-07-13T21:29:38

The result will be a polynomial of degree $6$ $6$

If you multiply polynomials the resulting polynomial will have a degree equal to sum of degrees of the factors.

In this case you have 3 polynomials of degrees: 2,1 and 3, so the result will be a polynomial of degree $2 + 1 + 3 = 6$ $2+1+3=6$

What is the degree of -5x^2(x-7)(x+1)^3=0−5x2(x−7)(x+1)3=0-5x^2(x-7)(x+1)^3=0?