What is the degree of $P (x) = x^{3} (x + 2) {(x - 3)}^{2}$ $P(x) = x^3(x+2)(x-3)^2$ ?

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What is the degree of $P (x) = x^{3} (x + 2) {(x - 3)}^{2}$ $P(x) = x^3(x+2)(x-3)^2$ ?

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Answer 1 · 2018-05-31T03:46:05

The degree of $P (x)$ $P(x)$ is 6.

Explanation:

The degree of a polynomial is the largest exponent of its variable (after all factors are distributed).

If we multiply the given factors out, we can guarantee we'll have an $x^{3} \times x \times x^{2}$ $x^3 xx x xx x^2$ term, and the exponent of this term is $3 + 1 + 2 = 6$ $3+1+2=6$ . All other terms will have $x$ $x$ to a lower power, and so 6 is the degree of this polynomial.

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What is the degree of $P (x) = x^{3} (x + 2) {(x - 3)}^{2}$ $P(x) = x^3(x+2)(x-3)^2$ ?

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What is the degree of P(x) = x^3(x+2)(x-3)^2P(x)=x3(x+2)(x−3)2P(x) = x^3(x+2)(x-3)^2?

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What is the degree of $P (x) = x^{3} (x + 2) {(x - 3)}^{2}$ $P(x) = x^3(x+2)(x-3)^2$ ?