What is the derivative of #arctan(x/a)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer James May 16, 2018 #d/dx[arctan(x/a)]=[1/a]/[1+(x/a)^2]=1/[a(1+(x/a)^2)]# Explanation: show below #d/dx[arctan(x/a)]=[1/a]/[1+(x/a)^2]=1/[a(1+(x/a)^2)]# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 15404 views around the world You can reuse this answer Creative Commons License