Question

What is the derivative of `e^cosx + cos(e^x)`?

Answer 1

`f' = -e^(cosx)sinx-e^xsine^x`

Explanation:

`f'=(e^(cosx)+cose^x)' = e^(cosx)(-sinx)-sine^x* e^x`

`f' = -e^(cosx)sinx-e^xsine^x`