Question

What is the derivative of `f(t) = (2t-e^t, 2t^2-t )`?

Answer 1

`(4t-1)/(2-e^t)`

Explanation:

`x=2t-e^t`

`dx/dt=2-e^t`

and

`y=2t^2-t`

`dy/dt=4t-1`

`f'(t)=dy/dx=(dy/dt)/(dx/dt)=(4t-1)/(2-e^t)`