What is the derivative of #f(t) = (t^2-sint , t-1 ) #?

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Answer 1 · 2018-04-03T17:00:45

#dy/dx = 2t-cos(t)#

#dy/dt =dy/dx dx/dt#

Solving for #dy/dx#:

#dy/dx = (dy/dt)/(dx/dt)#

Compute the required derivatives:

#dy/dt = 2t -cos(t)#

#dx/dt = 1#

Divide the derivatives as specified:

#dy/dx = (2t -cos(t))/1#

#dy/dx = 2t-cos(t)#