What is the derivative of f(x)=cos^2(x^3)f(x)=cos2(x3)?

1 Answer
Nov 16, 2015

f'(x)=-6x^2cos(x^3)sin(x^3)

Explanation:

Use the Chain Rule.

f'(x)=2cos(x^3)d/(dx)[cos(x^3)]

Now, using the chain rule again, we can find d/(dx)[cos(x^3)].
d/(dx)[cos(x^3)]=-sin(x^3)d/(dx)[x^3]=-3x^2sin(x^3)

So, f'(x)=2cos(x^3)*-3x^2sin(x^3)=-6x^2cos(x^3)sin(x^3)