What is the derivative of f(x)=esinxcos(ex)?

1 Answer
Oct 30, 2015

I found: f`(x)=esin(x)cos(x)+exsin(ex)

Explanation:

Here I would use the Chain Rule to deal with the function of a function as in esin(x) and cos(ex) by deriving the first one (in red) and then multiplying by the derivative of the second (in blue):

f`(x)=esin(x)cos(x)(sin(ex)ex)=

=esin(x)cos(x)+exsin(ex)