What is the derivative of #f(x) = tan( 2x^2 )#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Trevor Ryan. Dec 30, 2015 #4xsec^2(2x^2)# Explanation: Using the rule #d/dxtan[u(x)]=sec^2[u(x)]*(du)/(dx)#. #therefored/dxtan(2x^2)=sec^2(2x^2)*(4x)# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 3716 views around the world You can reuse this answer Creative Commons License